| Departure: | Dandenong, VIC |
| Arrival: | Rosedale, VIC |
| Fastest route: | 1h 50min |
| Distance: | 160km |
| Cheapest route: | $16.6 |
| Transfers: | Between 0 and 1 |
| Train companies: | V/Line |
One Passenger / One Trip
08:40
Dandenong, VIC
Dandenong Station
10:30
Rosedale, VIC
Rosedale Station
1h 50min
V/Line
$16.6
11:00
Dandenong, VIC
Dandenong Station
12:52
Rosedale, VIC
Rosedale Station
1h 52min
V/Line
$16.6
11:00
Dandenong, VIC
Dandenong Station
14:23
Rosedale, VIC
Rosedale Station
3h 23min
+
$25.8
11:00
Dandenong, VIC
Dandenong Station
13:13
Sale, VIC
Sale Station: Pettit Street
2h 13min
V/Line
$21.4
0h 52min layover
14:05
Sale, VIC
Sale Station: Pettit Street
14:23
Rosedale, VIC
Rosedale Station
0h 18min
V/Line
$4.4
18:59
Dandenong, VIC
Dandenong Station
20:51
Rosedale, VIC
Rosedale Station
1h 52min
V/Line
$16.6
The Dandenong - Rosedale route has approximately 4 frequencies and its minimum duration is around 1h 50min. It is important you book your ticket in advance to avoid running out, since $16.6 tickets tend to run out quickly.
The distance between Dandenong and Rosedale is around 160 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 1h 50min to cover 160 kilometers.
According to our data, the cheapest ticket costs $16.6 and leaves Dandenong Station. You will not have to do any transfers, the trip will go direct to Rosedale Station.
The last train leaves at 18:59 from Dandenong Station and arrives at 20:51 at Rosedale Station. It will take 1h 52min, its price is $16.6 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 1h 50min and the price is $16.6.