| Departure: | Kyneton, VIC |
| Arrival: | Swan Hill, VIC |
| Fastest route: | 3h 13min |
| Distance: | 260km |
| Cheapest route: | $34.79 |
| Transfers: | 0 |
| Train companies: | V/Line |
One Passenger / One Trip
09:14
Kyneton, VIC
Kyneton Station
12:32
Swan Hill, VIC
Swan Hill Station
3h 18min
V/Line
$34.79
19:52
Kyneton, VIC
Kyneton Station
23:05
Swan Hill, VIC
Swan Hill Station
3h 13min
V/Line
$34.79
The Kyneton - Swan Hill route has approximately 2 frequencies and its minimum duration is around 3h 13min. It is important you book your ticket in advance to avoid running out, since $34.79 tickets tend to run out quickly.
The distance between Kyneton and Swan Hill is around 260 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 3h 13min to cover 260 kilometers.
According to our data, the cheapest ticket costs $34.79 and leaves Kyneton Station. You will not have to do any transfers, the trip will go direct to Swan Hill Station.
The last train leaves at 19:52 from Kyneton Station and arrives at 23:05 at Swan Hill Station. It will take 3h 13min, its price is $34.79 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 3h 18min and the price is $34.79.