Departure: | Pakenham, VIC |
Arrival: | Rosedale, VIC |
Fastest route: | 1h 30min |
Distance: | 131km |
Cheapest route: | $16.6 |
Transfers: | Between 0 and 1 |
Train companies: | V/Line |
One Passenger / One Trip
08:57
Pakenham, VIC
Pakenham Station
10:30
Rosedale, VIC
Rosedale Station
1h 33min
V/Line
$16.6
11:17
Pakenham, VIC
Pakenham Station
12:52
Rosedale, VIC
Rosedale Station
1h 35min
V/Line
$16.6
11:17
Pakenham, VIC
Pakenham Station
14:23
Rosedale, VIC
Rosedale Station
3h 6min
+
$25.8
11:17
Pakenham, VIC
Pakenham Station
13:13
Sale, VIC
Sale Station: Pettit Street
1h 56min
V/Line
$21.4
0h 52min layover
14:05
Sale, VIC
Sale Station: Pettit Street
14:23
Rosedale, VIC
Rosedale Station
0h 18min
V/Line
$4.4
19:21
Pakenham, VIC
Pakenham Station
20:51
Rosedale, VIC
Rosedale Station
1h 30min
V/Line
$16.6
The Pakenham - Rosedale route has approximately 4 frequencies and its minimum duration is around 1h 30min. It is important you book your ticket in advance to avoid running out, since $16.6 tickets tend to run out quickly.
The distance between Pakenham and Rosedale is around 131 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 1h 30min to cover 131 kilometers.
According to our data, the cheapest ticket costs $16.6 and leaves Pakenham Station. You will not have to do any transfers, the trip will go direct to Rosedale Station.
The last train leaves at 19:21 from Pakenham Station and arrives at 20:51 at Rosedale Station. It will take 1h 30min, its price is $16.6 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 1h 33min and the price is $16.6.