Departure: | Terang, VIC |
Arrival: | Deer Park, VIC |
Fastest route: | 2h 38min |
Distance: | 196km |
Cheapest route: | $24 |
Transfers: | 0 |
Train companies: | V/Line |
One Passenger / One Trip
08:11
Terang, VIC
Terang Station
10:59
Deer Park, VIC
Deer Park Station
2h 48min
V/Line
$24
12:21
Terang, VIC
Terang Station
14:59
Deer Park, VIC
Deer Park Station
2h 38min
V/Line
$24
The Terang - Deer Park route has approximately 2 frequencies and its minimum duration is around 2h 38min. It is important you book your ticket in advance to avoid running out, since $24 tickets tend to run out quickly.
The distance between Terang and Deer Park is around 196 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 2h 38min to cover 196 kilometers.
According to our data, the cheapest ticket costs $24 and leaves Terang Station. You will not have to do any transfers, the trip will go direct to Deer Park Station.
The last train leaves at 12:21 from Terang Station and arrives at 14:59 at Deer Park Station. It will take 2h 38min, its price is $24 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 2h 48min and the price is $24.