Departure: | Terang, VIC |
Arrival: | Warrnambool, VIC |
Fastest route: | 0h 38min |
Distance: | 47km |
Cheapest route: | $5.4 |
Transfers: | 0 |
Train companies: | V/Line |
One Passenger / One Trip
10:15
Terang, VIC
Terang Station
11:10
Warrnambool, VIC
Warrnambool Station
0h 55min
V/Line
$5.4
16:00
Terang, VIC
Terang Station
16:38
Warrnambool, VIC
Warrnambool Station
0h 38min
V/Line
$5.4
20:16
Terang, VIC
Terang Station
21:00
Warrnambool, VIC
Warrnambool Station
0h 44min
V/Line
$5.4
22:06
Terang, VIC
Terang Station
22:49
Warrnambool, VIC
Warrnambool Station
0h 43min
V/Line
$5.4
The Terang - Warrnambool route has approximately 4 frequencies and its minimum duration is around 0h 38min. It is important you book your ticket in advance to avoid running out, since $5.4 tickets tend to run out quickly.
The distance between Terang and Warrnambool is around 47 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 0h 38min to cover 47 kilometers.
According to our data, the cheapest ticket costs $5.4 and leaves Terang Station. You will not have to do any transfers, the trip will go direct to Warrnambool Station.
The last train leaves at 22:06 from Terang Station and arrives at 22:49 at Warrnambool Station. It will take 0h 43min, its price is $5.4 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 0h 55min and the price is $5.4.