Departure: | Warragul, VIC |
Arrival: | Rosedale, VIC |
Fastest route: | 1h 0min |
Distance: | 85km |
Cheapest route: | $9.19 |
Transfers: | Between 0 and 1 |
Train companies: | V/Line |
One Passenger / One Trip
09:30
Warragul, VIC
Warragul Station
10:30
Rosedale, VIC
Rosedale Station
1h 0min
V/Line
$9.19
11:52
Warragul, VIC
Warragul Station
12:52
Rosedale, VIC
Rosedale Station
1h 0min
V/Line
$9.19
11:52
Warragul, VIC
Warragul Station
14:23
Rosedale, VIC
Rosedale Station
2h 31min
+
$17.8
11:52
Warragul, VIC
Warragul Station
13:13
Sale, VIC
Sale Station: Pettit Street
1h 21min
V/Line
$13.4
0h 52min layover
14:05
Sale, VIC
Sale Station: Pettit Street
14:23
Rosedale, VIC
Rosedale Station
0h 18min
V/Line
$4.4
19:51
Warragul, VIC
Warragul Station
20:51
Rosedale, VIC
Rosedale Station
1h 0min
V/Line
$9.19
The Warragul - Rosedale route has approximately 4 frequencies and its minimum duration is around 1h 0min. It is important you book your ticket in advance to avoid running out, since $9.19 tickets tend to run out quickly.
The distance between Warragul and Rosedale is around 85 kilometers and bus companies that can help you in your journey are: V/Line.
The train journey may vary depending on the stops. The minimum duration is usually around 1h 0min to cover 85 kilometers.
According to our data, the cheapest ticket costs $9.19 and leaves Warragul Station. You will not have to do any transfers, the trip will go direct to Rosedale Station.
The last train leaves at 19:51 from Warragul Station and arrives at 20:51 at Rosedale Station. It will take 1h 0min, its price is $9.19 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 1h 0min and the price is $9.19.