| Departure: | Columbus, OH |
| Arrival: | Fayetteville, AR |
| Fastest route: | 41h 50min |
| Distance: | 1232km |
| Cheapest route: | $220.5 |
| Transfers: | 2 |
| Bus companies: | Greyhound, Barons Bus |
One Passenger / One Trip
3:15pm
Columbus, OH
Columbus International Airport
8:05am
Fayetteville, AR
Fayetteville Bus Station
41h 50min
++
$220.5
Multiple companies
3:15pm
Columbus, OH
Columbus International Airport
10:00pm
Indianapolis, IN
Bus Station
6h 45min
Barons Bus
$32
2h 30min layover
12:30am
Indianapolis, IN
Bus Station
9:40pm
Dallas, TX
Downtown Greyhound Station
22h 10min
Greyhound
$115.5
2h 10min layover
11:50pm
Dallas, TX
Downtown Greyhound Station
8:05am
Fayetteville, AR
Fayetteville Bus Station
8h 15min
Greyhound
$73
The Columbus - Fayetteville route has approximately 1 frequencies and its minimum duration is around 41h 50min. It is important you book your ticket in advance to avoid running out, since $220.5 tickets tend to run out quickly.
The distance between Columbus and Fayetteville is around 1232 kilometers and the bus companies that can help you in your journey are: Greyhound, Barons Bus.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
Bus journey may vary depending on the state of the roads. The minimum duration is usually around 41h 50min to cover 1232 kilometers.
According to our data, the cheapest ticket costs $220.5 and leaves Columbus International Airport. If you decide to make this journey you will have to do 2 stops before reaching Fayetteville Bus Station.
Last bus leaves at 3:15pm from Columbus International Airport and arrives at 8:05am at Fayetteville Bus Station. It will take 41h 50min, its price is $220.5 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 and the total duration of the trip will be approximately 41h 50min.