| Departure: | Melville, SK |
| Arrival: | Abbotsford, BC |
| Fastest route: | 38h 29min |
| Distance: | 1620km |
| Cheapest route: | CDN$ 246.75 |
| Transfers: | Between 0 and 1 |
| Train companies: | VIA Rail |
One Passenger / One Trip
5:39pm
Melville, SK
Melville train station
7:08am
Abbotsford, BC
Abbotsford train station
38h 29min
VIA Rail
CDN$ 246.75
5:39pm
Melville, SK
Melville train station
7:08am
Abbotsford, BC
Abbotsford train station
38h 29min
+
CDN$ 283.5
5:39pm
Melville, SK
Melville train station
6:22am
Edmonton, AB
Edmonton train station
12h 43min
VIA Rail
CDN$ 101.85
1h 15min layover
7:37am
Edmonton, AB
Edmonton train station
7:08am
Abbotsford, BC
Abbotsford train station
24h 31min
VIA Rail
CDN$ 181.65
The Melville - Abbotsford route has approximately 2 frequencies and its minimum duration is around 38h 29min. It is important you book your ticket in advance to avoid running out, since CDN$ 246.75 tickets tend to run out quickly.
The distance between Melville and Abbotsford is around 1620 kilometers and bus companies that can help you in your journey are: VIA Rail.
The train journey may vary depending on the stops. The minimum duration is usually around 38h 29min to cover 1620 kilometers.
According to our data, the cheapest ticket costs CDN$ 246.75 and leaves Melville train station. You will not have to do any transfers, the trip will go direct to Abbotsford train station.
The last train leaves at 5:39pm from Melville train station and arrives at 7:08am at Abbotsford train station. It will take 38h 29min, its price is CDN$ 283.5 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 38h 29min and the price is CDN$ 246.75.