Departure: | Oakbank, MB |
Arrival: | Wainwright, AB |
Fastest route: | 22h 45min |
Distance: | 1278km |
Cheapest route: | CDN$ 152.25 |
Transfers: | Between 0 and 1 |
Train companies: | VIA Rail |
One Passenger / One Trip
5:18am
Oakbank, MB
Brereton Lake train station
3:03am
Wainwright, AB
Wainwright train station
22h 45min
VIA Rail
CDN$ 152.25
5:18am
Oakbank, MB
Brereton Lake train station
3:03am
Wainwright, AB
Wainwright train station
22h 45min
+
CDN$ 163.8
5:18am
Oakbank, MB
Brereton Lake train station
11:49pm
Biggar, SK
Biggar train station
19h 31min
VIA Rail
CDN$ 128.1
0h 10min layover
11:59pm
Biggar, SK
Biggar train station
3:03am
Wainwright, AB
Wainwright train station
3h 4min
VIA Rail
CDN$ 35.7
The Oakbank - Wainwright route has approximately 2 frequencies and its minimum duration is around 22h 45min. It is important you book your ticket in advance to avoid running out, since CDN$ 152.25 tickets tend to run out quickly.
The distance between Oakbank and Wainwright is around 1278 kilometers and bus companies that can help you in your journey are: VIA Rail.
The train journey may vary depending on the stops. The minimum duration is usually around 22h 45min to cover 1278 kilometers.
According to our data, the cheapest ticket costs CDN$ 152.25 and leaves Brereton Lake train station. You will not have to do any transfers, the trip will go direct to Wainwright train station.
The last train leaves at 5:18am from Brereton Lake train station and arrives at 3:03am at Wainwright train station. It will take 22h 45min, its price is CDN$ 163.8 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 22h 45min and the price is CDN$ 152.25.