Departure: | Sioux Lookout, ON |
Arrival: | Abbotsford, BC |
Fastest route: | 56h 59min |
Distance: | 2510km |
Cheapest route: | CDN$ 342.39 |
Transfers: | Between 0 and 1 |
Train companies: | VIA Rail |
One Passenger / One Trip
12:09am
Sioux Lookout, ON
Sioux Lookout train station
7:08am
Abbotsford, BC
Abbotsford train station
56h 59min
VIA Rail
CDN$ 342.39
12:09am
Sioux Lookout, ON
Sioux Lookout train station
7:08am
Abbotsford, BC
Abbotsford train station
56h 59min
+
CDN$ 408.95
12:09am
Sioux Lookout, ON
Sioux Lookout train station
6:22am
Edmonton, AB
Edmonton train station
31h 13min
VIA Rail
CDN$ 214.7
1h 15min layover
7:37am
Edmonton, AB
Edmonton train station
7:08am
Abbotsford, BC
Abbotsford train station
24h 31min
VIA Rail
CDN$ 194.25
The Sioux Lookout - Abbotsford route has approximately 2 frequencies and its minimum duration is around 56h 59min. It is important you book your ticket in advance to avoid running out, since CDN$ 342.39 tickets tend to run out quickly.
The distance between Sioux Lookout and Abbotsford is around 2510 kilometers and bus companies that can help you in your journey are: VIA Rail.
The train journey may vary depending on the stops. The minimum duration is usually around 56h 59min to cover 2510 kilometers.
According to our data, the cheapest ticket costs CDN$ 342.39 and leaves Sioux Lookout train station. You will not have to do any transfers, the trip will go direct to Abbotsford train station.
The last train leaves at 12:09am from Sioux Lookout train station and arrives at 7:08am at Abbotsford train station. It will take 56h 59min, its price is CDN$ 408.95 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 56h 59min and the price is CDN$ 342.39.