Departure: | Cleveland, OH |
Arrival: | Harpers Ferry, WV |
Fastest route: | 9h 37min |
Distance: | 475km |
Cheapest route: | $58 |
Transfers: | Between 0 and 1 |
Train companies: | Amtrak |
One Passenger / One Trip
1:54am
Cleveland, OH
Cleveland
11:31am
Harpers Ferry, WV
Harpers Ferry
9h 37min
Amtrak
Capitol Limited
$65
1:54am
Cleveland, OH
Cleveland
11:31am
Harpers Ferry, WV
Harpers Ferry
9h 37min
+
$58
1:54am
Cleveland, OH
Cleveland
5:05am
Pittsburgh, PA
Pittsburgh
3h 11min
Amtrak
Capitol Limited
$23
0h 15min layover
5:20am
Pittsburgh, PA
Pittsburgh
11:31am
Harpers Ferry, WV
Harpers Ferry
6h 11min
Amtrak
Capitol Limited
$35
The Cleveland - Harpers Ferry route has approximately 2 frequencies and its minimum duration is around 9h 37min. It is important you book your ticket in advance to avoid running out, since $58 tickets tend to run out quickly.
The distance between Cleveland and Harpers Ferry is around 475 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 9h 37min to cover 475 kilometers.
According to our data, the cheapest ticket costs $58 and leaves Cleveland. If you decide to make this journey you will have to do 1 stop before reaching Harpers Ferry.
The last train leaves at 1:54am from Cleveland and arrives at 11:31am at Harpers Ferry. It will take 9h 37min, its price is $58 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 9h 37min and the price is $65.