Trip information

Departure: Cleveland, OH
Arrival: Martinsburg, WV
Fastest route: 9h 7min
Distance: 447km
Cheapest route: $50
Transfers: 0
Train companies: Amtrak

Cheap train schedules leaving on Thursday

One Passenger / One Trip

1:54am

Cleveland, OH

Cleveland

11:01am

Martinsburg, WV

Martinsburg

9h 7min

Amtrak
Capitol Limited

$50

Overview

Traveling from Cleveland to Martinsburg by train

First departure
1:54am
Avg price
$50
Carriers
1
Last arrival
11:01am

Train information Cleveland - Martinsburg

The Cleveland - Martinsburg route has approximately 1 frequencies and its minimum duration is around 9h 7min. It is important you book your ticket in advance to avoid running out, since $50 tickets tend to run out quickly.
The distance between Cleveland and Martinsburg is around 447 kilometers and bus companies that can help you in your journey are: Amtrak.

  • Trips per day 1
  • Direct trips 1

How long does it take to get from Cleveland to Martinsburg by train?

The train journey may vary depending on the stops. The minimum duration is usually around 9h 7min to cover 447 kilometers.

I'm looking for cheap tickets for this route ...

According to our data, the cheapest ticket costs $50 and leaves Cleveland. You will not have to do any transfers, the trip will go direct to Martinsburg.

  • Avg duration 9h 7min
  • Cheapest price $50

What time does the last train leave?

The last train leaves at 1:54am from Cleveland and arrives at 11:01am at Martinsburg. It will take 9h 7min, its price is $50 and the number of changes will be 0.

Are there any direct routes between Cleveland and Martinsburg?

Yes, there are direct train routes, their duration is usually around 9h 7min and the price is $50.

  • Last train 1:54am
  • Transfers 0

What are the train stations in Cleveland?

  • Cleveland

What are the train stations in Martinsburg?

  • Martinsburg
We use cookies to enhance your browsing experience. By using this site, you agree to our use of cookies. More information: Cookies Policy