Departure: | Cleveland, OH |
Arrival: | Sandusky, OH |
Fastest route: | 1h 3min |
Distance: | 97km |
Cheapest route: | $12 |
Transfers: | 0 |
Train companies: | Amtrak |
One Passenger / One Trip
2:59am
Cleveland, OH
Cleveland
4:02am
Sandusky, OH
Sandusky
1h 3min
Amtrak
Capitol Limited
$12
3:45am
Cleveland, OH
Cleveland
4:55am
Sandusky, OH
Sandusky
1h 10min
Amtrak
Lake Shore Limited
$12
3:45am
Cleveland, OH
Cleveland
4:55am
Sandusky, OH
Sandusky
1h 10min
Amtrak
Lake Shore Limited
$12
The Cleveland - Sandusky route has approximately 3 frequencies and its minimum duration is around 1h 3min. It is important you book your ticket in advance to avoid running out, since $12 tickets tend to run out quickly.
The distance between Cleveland and Sandusky is around 97 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 1h 3min to cover 97 kilometers.
According to our data, the cheapest ticket costs $12 and leaves Cleveland. You will not have to do any transfers, the trip will go direct to Sandusky.
The last train leaves at 3:45am from Cleveland and arrives at 4:55am at Sandusky. It will take 1h 10min, its price is $12 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 1h 3min and the price is $12.