Departure: | Cleveland, OH |
Arrival: | Waterloo, IN |
Fastest route: | 3h 37min |
Distance: | 318km |
Cheapest route: | $29 |
Transfers: | 0 |
Train companies: | Amtrak |
One Passenger / One Trip
2:59am
Cleveland, OH
Cleveland
6:36am
Waterloo, IN
Waterloo
3h 37min
Amtrak
Capitol Limited
$46
3:45am
Cleveland, OH
Cleveland
7:33am
Waterloo, IN
Waterloo
3h 48min
Amtrak
Lake Shore Limited
$29
3:45am
Cleveland, OH
Cleveland
7:33am
Waterloo, IN
Waterloo
3h 48min
Amtrak
Lake Shore Limited
$29
The Cleveland - Waterloo route has approximately 3 frequencies and its minimum duration is around 3h 37min. It is important you book your ticket in advance to avoid running out, since $29 tickets tend to run out quickly.
The distance between Cleveland and Waterloo is around 318 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 3h 37min to cover 318 kilometers.
According to our data, the cheapest ticket costs $29 and leaves Cleveland. You will not have to do any transfers, the trip will go direct to Waterloo.
The last train leaves at 3:45am from Cleveland and arrives at 7:33am at Waterloo. It will take 3h 48min, its price is $29 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 3h 37min and the price is $46.