Departure: | Fort Edward, NY |
Arrival: | Schenectady, NY |
Fastest route: | 0h 57min |
Distance: | 66km |
Cheapest route: | $18 |
Transfers: | Between 0 and 1 |
Train companies: | Amtrak |
One Passenger / One Trip
9:31am
Fort Edward, NY
Fort Edward-Glens Falls
10:28am
Schenectady, NY
Schenectady
0h 57min
Amtrak
Ethan Allen Express
$18
9:31am
Fort Edward, NY
Fort Edward-Glens Falls
11:33am
Schenectady, NY
Schenectady
2h 2min
+
$33
9:31am
Fort Edward, NY
Fort Edward-Glens Falls
10:50am
Rensselaer, NY
Albany-Rensselaer
1h 19min
Amtrak
Ethan Allen Express
$20
0h 20min layover
11:10am
Rensselaer, NY
Albany-Rensselaer
11:33am
Schenectady, NY
Schenectady
0h 23min
Amtrak
Adirondack
$13
4:16pm
Fort Edward, NY
Fort Edward-Glens Falls
5:18pm
Schenectady, NY
Schenectady
1h 2min
Amtrak
Adirondack
$18
The Fort Edward - Schenectady route has approximately 3 frequencies and its minimum duration is around 0h 57min. It is important you book your ticket in advance to avoid running out, since $18 tickets tend to run out quickly.
The distance between Fort Edward and Schenectady is around 66 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 0h 57min to cover 66 kilometers.
According to our data, the cheapest ticket costs $18 and leaves Fort Edward-Glens Falls. You will not have to do any transfers, the trip will go direct to Schenectady.
The last train leaves at 4:16pm from Fort Edward-Glens Falls and arrives at 5:18pm at Schenectady. It will take 1h 2min, its price is $18 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 0h 57min and the price is $18.