Departure: | Fort Edward, NY |
Arrival: | Schenectady, NY |
Fastest route: | 0h 58min |
Distance: | 66km |
Cheapest route: | $18 |
Transfers: | Between 0 and 1 |
Train companies: | Amtrak |
One Passenger / One Trip
4:16pm
Fort Edward, NY
Fort Edward-Glens Falls
5:18pm
Schenectady, NY
Schenectady
1h 2min
Amtrak
Adirondack
$18
4:16pm
Fort Edward, NY
Fort Edward-Glens Falls
6:24pm
Schenectady, NY
Schenectady
2h 8min
+
$33
4:16pm
Fort Edward, NY
Fort Edward-Glens Falls
5:40pm
Rensselaer, NY
Albany-Rensselaer
1h 24min
Amtrak
Adirondack
$20
0h 20min layover
6:00pm
Rensselaer, NY
Albany-Rensselaer
6:24pm
Schenectady, NY
Schenectady
0h 24min
Amtrak
Ethan Allen Express
$13
6:25pm
Fort Edward, NY
Fort Edward-Glens Falls
7:23pm
Schenectady, NY
Schenectady
0h 58min
Amtrak
Ethan Allen Express
$18
The Fort Edward - Schenectady route has approximately 3 frequencies and its minimum duration is around 0h 58min. It is important you book your ticket in advance to avoid running out, since $18 tickets tend to run out quickly.
The distance between Fort Edward and Schenectady is around 66 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 0h 58min to cover 66 kilometers.
According to our data, the cheapest ticket costs $18 and leaves Fort Edward-Glens Falls. You will not have to do any transfers, the trip will go direct to Schenectady.
The last train leaves at 6:25pm from Fort Edward-Glens Falls and arrives at 7:23pm at Schenectady. It will take 0h 58min, its price is $18 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 1h 2min and the price is $18.