Departure: | Harpers Ferry, WV |
Arrival: | Sandusky, OH |
Fastest route: | 10h 46min |
Distance: | 554km |
Cheapest route: | $67 |
Transfers: | Between 0 and 1 |
Train companies: | Amtrak |
One Passenger / One Trip
5:16pm
Harpers Ferry, WV
Harpers Ferry
4:02am
Sandusky, OH
Sandusky
10h 46min
Amtrak
Capitol Limited
$69
5:16pm
Harpers Ferry, WV
Harpers Ferry
4:02am
Sandusky, OH
Sandusky
10h 46min
+
$67
5:16pm
Harpers Ferry, WV
Harpers Ferry
2:53am
Cleveland, OH
Cleveland
9h 37min
Amtrak
Capitol Limited
$52
0h 6min layover
2:59am
Cleveland, OH
Cleveland
4:02am
Sandusky, OH
Sandusky
1h 3min
Amtrak
Capitol Limited
$15
The Harpers Ferry - Sandusky route has approximately 2 frequencies and its minimum duration is around 10h 46min. It is important you book your ticket in advance to avoid running out, since $67 tickets tend to run out quickly.
The distance between Harpers Ferry and Sandusky is around 554 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 10h 46min to cover 554 kilometers.
According to our data, the cheapest ticket costs $67 and leaves Harpers Ferry. If you decide to make this journey you will have to do 1 stop before reaching Sandusky.
The last train leaves at 5:16pm from Harpers Ferry and arrives at 4:02am at Sandusky. It will take 10h 46min, its price is $67 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 10h 46min and the price is $69.