Trip information

Departure: Martinsburg, WV
Arrival: Cleveland, OH
Fastest route: 9h 8min
Distance: 447km
Cheapest route: $50
Transfers: 0
Train companies: Amtrak

Cheap train schedules leaving on Thursday

One Passenger / One Trip

5:45pm

Martinsburg, WV

Martinsburg

2:53am

Cleveland, OH

Cleveland

9h 8min

Amtrak
Capitol Limited

$50

Overview

Traveling from Martinsburg to Cleveland by train

First departure
5:45pm
Avg price
$50
Carriers
1
Last arrival
2:53am

Train information Martinsburg - Cleveland

The Martinsburg - Cleveland route has approximately 1 frequencies and its minimum duration is around 9h 8min. It is important you book your ticket in advance to avoid running out, since $50 tickets tend to run out quickly.
The distance between Martinsburg and Cleveland is around 447 kilometers and bus companies that can help you in your journey are: Amtrak.

  • Trips per day 1
  • Direct trips 1

How long does it take to get from Martinsburg to Cleveland by train?

The train journey may vary depending on the stops. The minimum duration is usually around 9h 8min to cover 447 kilometers.

I'm looking for cheap tickets for this route ...

According to our data, the cheapest ticket costs $50 and leaves Martinsburg. You will not have to do any transfers, the trip will go direct to Cleveland.

  • Avg duration 9h 8min
  • Cheapest price $50

What time does the last train leave?

The last train leaves at 5:45pm from Martinsburg and arrives at 2:53am at Cleveland. It will take 9h 8min, its price is $50 and the number of changes will be 0.

Are there any direct routes between Martinsburg and Cleveland?

Yes, there are direct train routes, their duration is usually around 9h 8min and the price is $50.

  • Last train 5:45pm
  • Transfers 0

What are the train stations in Martinsburg?

  • Martinsburg

What are the train stations in Cleveland?

  • Cleveland
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