Departure: | Mineola, TX |
Arrival: | Kewanee, IL |
Fastest route: | 0h 43min |
Distance: | 1235km |
Cheapest route: | $8 |
Transfers: | 1 |
Train companies: | Amtrak |
One Passenger / One Trip
9:00am
Mineola, TX
Mineola
9:43am
Kewanee, IL
Kewanee
0h 43min
+
$8
9:00am
Mineola, TX
Mineola
9:20am
Princeton, IL
Princeton
0h 20min
Amtrak
Carl Sandburg
$3.5
0h 1min layover
9:21am
Princeton, IL
Princeton
9:43am
Kewanee, IL
Kewanee
0h 22min
Amtrak
Carl Sandburg
$4.5
4:24pm
Mineola, TX
Mineola
8:03pm
Kewanee, IL
Kewanee
3h 39min
+
$9.5
4:24pm
Mineola, TX
Mineola
4:46pm
Princeton, IL
Princeton
0h 22min
Amtrak
Southwest Chief
$5
2h 55min layover
7:41pm
Princeton, IL
Princeton
8:03pm
Kewanee, IL
Kewanee
0h 22min
Amtrak
Illinois Zephyr
$4.5
7:20pm
Mineola, TX
Mineola
8:03pm
Kewanee, IL
Kewanee
0h 43min
+
$8
7:20pm
Mineola, TX
Mineola
7:40pm
Princeton, IL
Princeton
0h 20min
Amtrak
Illinois Zephyr
$3.5
0h 1min layover
7:41pm
Princeton, IL
Princeton
8:03pm
Kewanee, IL
Kewanee
0h 22min
Amtrak
Illinois Zephyr
$4.5
The Mineola - Kewanee route has approximately 3 frequencies and its minimum duration is around 0h 43min. It is important you book your ticket in advance to avoid running out, since $8 tickets tend to run out quickly.
The distance between Mineola and Kewanee is around 1235 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 1 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 0h 43min to cover 1235 kilometers.
According to our data, the cheapest ticket costs $8 and leaves Mineola. If you decide to make this journey you will have to do 1 stop before reaching Kewanee.
The last train leaves at 7:20pm from Mineola and arrives at 8:03pm at Kewanee. It will take 0h 43min, its price is $8 and the number of changes will be 1.
We do not have direct routes in our database. The minimum number of transfers will be 1 transshipments and the total duration of the trip will be approximately 0h 43min