Departure: | Normal, IL |
Arrival: | Alpine, TX |
Fastest route: | 42h 24min |
Distance: | 2001km |
Cheapest route: | $107 |
Transfers: | Between 0 and 2 |
Train companies: | Amtrak |
One Passenger / One Trip
11:39am
Normal, IL
Bloomington-Normal
10:28am
Alpine, TX
Alpine
46h 49min
++
$167.5
11:39am
Normal, IL
Bloomington-Normal
12:10pm
Lincoln, IL
Lincoln
0h 31min
Amtrak
Lincoln Service
$3.5
4h 27min layover
4:37pm
Lincoln, IL
Lincoln
6:22pm
Austin, TX
Austin
25h 45min
Amtrak
Texas Eagle
$107
0h 8min layover
6:30pm
Austin, TX
Austin
10:28am
Alpine, TX
Alpine
15h 58min
Amtrak
Texas Eagle
$57
4:04pm
Normal, IL
Bloomington-Normal
10:28am
Alpine, TX
Alpine
42h 24min
Amtrak
Texas Eagle
$107
The Normal - Alpine route has approximately 2 frequencies and its minimum duration is around 42h 24min. It is important you book your ticket in advance to avoid running out, since $107 tickets tend to run out quickly.
The distance between Normal and Alpine is around 2001 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 42h 24min to cover 2001 kilometers.
According to our data, the cheapest ticket costs $107 and leaves Bloomington-Normal. You will not have to do any transfers, the trip will go direct to Alpine.
The last train leaves at 4:04pm from Bloomington-Normal and arrives at 10:28am at Alpine. It will take 42h 24min, its price is $107 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 42h 24min and the price is $107.