| Departure: | Normal, IL |
| Arrival: | Austin, TX |
| Fastest route: | 26h 18min |
| Distance: | 1595km |
| Cheapest route: | $110.5 |
| Transfers: | Between 0 and 1 |
| Train companies: | Amtrak |
One Passenger / One Trip
11:39am
Normal, IL
Bloomington-Normal
6:22pm
Austin, TX
Austin
30h 43min
+
$110.5
11:39am
Normal, IL
Bloomington-Normal
12:10pm
Lincoln, IL
Lincoln
0h 31min
Amtrak
Lincoln Service
$3.5
4h 27min layover
4:37pm
Lincoln, IL
Lincoln
6:22pm
Austin, TX
Austin
25h 45min
Amtrak
Texas Eagle
$107
4:04pm
Normal, IL
Bloomington-Normal
6:22pm
Austin, TX
Austin
26h 18min
Amtrak
Texas Eagle
$134
4:04pm
Normal, IL
Bloomington-Normal
6:22pm
Austin, TX
Austin
26h 18min
Amtrak
Texas Eagle
$134
The Normal - Austin route has approximately 3 frequencies and its minimum duration is around 26h 18min. It is important you book your ticket in advance to avoid running out, since $110.5 tickets tend to run out quickly.
The distance between Normal and Austin is around 1595 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 26h 18min to cover 1595 kilometers.
According to our data, the cheapest ticket costs $110.5 and leaves Bloomington-Normal. If you decide to make this journey you will have to do 1 stop before reaching Austin.
The last train leaves at 4:04pm from Bloomington-Normal and arrives at 6:22pm at Austin. It will take 26h 18min, its price is $134 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 26h 18min and the price is $134.