Departure: | Normal, IL |
Arrival: | Mineola, TX |
Fastest route: | 17h 21min |
Distance: | 1204km |
Cheapest route: | $88 |
Transfers: | 0 |
Train companies: | Amtrak |
One Passenger / One Trip
4:04pm
Normal, IL
Bloomington-Normal
9:25am
Mineola, TX
Mineola
17h 21min
Amtrak
Texas Eagle
$110
4:04pm
Normal, IL
Bloomington-Normal
9:25am
Mineola, TX
Mineola
17h 21min
Amtrak
Texas Eagle
$88
The Normal - Mineola route has approximately 2 frequencies and its minimum duration is around 17h 21min. It is important you book your ticket in advance to avoid running out, since $88 tickets tend to run out quickly.
The distance between Normal and Mineola is around 1204 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 17h 21min to cover 1204 kilometers.
According to our data, the cheapest ticket costs $88 and leaves Bloomington-Normal. You will not have to do any transfers, the trip will go direct to Mineola.
The last train leaves at 4:04pm from Bloomington-Normal and arrives at 9:25am at Mineola. It will take 17h 21min, its price is $88 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 17h 21min and the price is $110.