Departure: | Oklahoma City, OK |
Arrival: | Deerfield Beach, FL |
Fastest route: | 12h 34min |
Distance: | 2236km |
Cheapest route: | $67 |
Transfers: | 0 |
Train companies: | Amtrak |
One Passenger / One Trip
5:51am
Oklahoma City, OK
Oklahoma City
6:25pm
Deerfield Beach, FL
Deerfield Beach
12h 34min
Amtrak
Silver Meteor
$67
The Oklahoma City - Deerfield Beach route has approximately 1 frequencies and its minimum duration is around 12h 34min. It is important you book your ticket in advance to avoid running out, since $67 tickets tend to run out quickly.
The distance between Oklahoma City and Deerfield Beach is around 2236 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 12h 34min to cover 2236 kilometers.
According to our data, the cheapest ticket costs $67 and leaves Oklahoma City. You will not have to do any transfers, the trip will go direct to Deerfield Beach.
The last train leaves at 5:51am from Oklahoma City and arrives at 6:25pm at Deerfield Beach. It will take 12h 34min, its price is $67 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 12h 34min and the price is $67.