Departure: | Oxnard, CA |
Arrival: | Fort Edward, NY |
Fastest route: | 22h 20min |
Distance: | 4633km |
Cheapest route: | $193 |
Transfers: | 2 |
Train companies: | Amtrak |
One Passenger / One Trip
7:54pm
Oxnard, CA
Oxnard
6:14pm
Fort Edward, NY
Fort Edward-Glens Falls
22h 20min
++
$193
7:54pm
Oxnard, CA
Oxnard
9:13pm
Burbank, CA
Burbank - Airport
1h 19min
Amtrak
Pacific Surfliner
$19
6h 3min layover
3:16am
Burbank, CA
Burbank - Airport
1:48pm
New York, NY
New York - Penn Station
10h 32min
Amtrak
Crescent
$116
0h 32min layover
2:20pm
New York, NY
New York - Penn Station
6:14pm
Fort Edward, NY
Fort Edward-Glens Falls
3h 54min
Amtrak
Ethan Allen Express
$58
The Oxnard - Fort Edward route has approximately 1 frequencies and its minimum duration is around 22h 20min. It is important you book your ticket in advance to avoid running out, since $193 tickets tend to run out quickly.
The distance between Oxnard and Fort Edward is around 4633 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 22h 20min to cover 4633 kilometers.
According to our data, the cheapest ticket costs $193 and leaves Oxnard. If you decide to make this journey you will have to do 2 stops before reaching Fort Edward-Glens Falls.
The last train leaves at 7:54pm from Oxnard and arrives at 6:14pm at Fort Edward-Glens Falls. It will take 22h 20min, its price is $193 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 22h 20min