| Departure: | Pennsauken Township, NJ |
| Arrival: | Hudson, NY |
| Fastest route: | 30h 58min |
| Distance: | 318km |
| Cheapest route: | $307 |
| Transfers: | 2 |
| Train companies: | Amtrak |
One Passenger / One Trip
8:22am
Pennsauken Township, NJ
Pennsauken - NJ Transit Service
4:20pm
Hudson, NY
Hudson
30h 58min
++
$307
8:22am
Pennsauken Township, NJ
Pennsauken - NJ Transit Service
12:08pm
Philadelphia, PA
Philadelphia - 30th Street Station
26h 46min
Amtrak
Crescent
$161
0h 28min layover
12:36pm
Philadelphia, PA
Philadelphia - 30th Street Station
1:50pm
New York, NY
New York - Penn Station
1h 14min
Amtrak
Acela Express
$108
0h 30min layover
2:20pm
New York, NY
New York - Penn Station
4:20pm
Hudson, NY
Hudson
2h 0min
Amtrak
Ethan Allen Express
$38
The Pennsauken Township - Hudson route has approximately 1 frequencies and its minimum duration is around 30h 58min. It is important you book your ticket in advance to avoid running out, since $307 tickets tend to run out quickly.
The distance between Pennsauken Township and Hudson is around 318 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 30h 58min to cover 318 kilometers.
According to our data, the cheapest ticket costs $307 and leaves Pennsauken - NJ Transit Service. If you decide to make this journey you will have to do 2 stops before reaching Hudson.
The last train leaves at 8:22am from Pennsauken - NJ Transit Service and arrives at 4:20pm at Hudson. It will take 30h 58min, its price is $307 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 30h 58min