Departure: | Rutland, VT |
Arrival: | McGregor, TX |
Fastest route: | 52h 50min |
Distance: | 2909km |
Cheapest route: | $221 |
Transfers: | 2 |
Train companies: | Amtrak |
One Passenger / One Trip
11:10am
Rutland, VT
Rutland
4:00pm
McGregor, TX
McGregor
52h 50min
++
$221
11:10am
Rutland, VT
Rutland
1:27pm
Schenectady, NY
Schenectady
2h 17min
Amtrak
Ethan Allen Express
$29
6h 5min layover
7:32pm
Schenectady, NY
Schenectady
9:45am
Chicago, IL
Chicago - Union Station
14h 13min
Amtrak
Lake Shore Limited
$80
4h 0min layover
1:45pm
Chicago, IL
Chicago - Union Station
4:00pm
McGregor, TX
McGregor
26h 15min
Amtrak
Texas Eagle
$112
The Rutland - McGregor route has approximately 1 frequencies and its minimum duration is around 52h 50min. It is important you book your ticket in advance to avoid running out, since $221 tickets tend to run out quickly.
The distance between Rutland and McGregor is around 2909 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 52h 50min to cover 2909 kilometers.
According to our data, the cheapest ticket costs $221 and leaves Rutland. If you decide to make this journey you will have to do 2 stops before reaching McGregor.
The last train leaves at 11:10am from Rutland and arrives at 4:00pm at McGregor. It will take 52h 50min, its price is $221 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 52h 50min