| Departure: | Sandusky, OH |
| Arrival: | Harpers Ferry, WV |
| Fastest route: | 10h 51min |
| Distance: | 554km |
| Cheapest route: | $55 |
| Transfers: | 0 |
| Train companies: | Amtrak |
One Passenger / One Trip
12:40am
Sandusky, OH
Sandusky
11:31am
Harpers Ferry, WV
Harpers Ferry
10h 51min
Amtrak
Capitol Limited
$55
The Sandusky - Harpers Ferry route has approximately 1 frequencies and its minimum duration is around 10h 51min. It is important you book your ticket in advance to avoid running out, since $55 tickets tend to run out quickly.
The distance between Sandusky and Harpers Ferry is around 554 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 10h 51min to cover 554 kilometers.
According to our data, the cheapest ticket costs $55 and leaves Sandusky. You will not have to do any transfers, the trip will go direct to Harpers Ferry.
The last train leaves at 12:40am from Sandusky and arrives at 11:31am at Harpers Ferry. It will take 10h 51min, its price is $55 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 10h 51min and the price is $55.