Departure: | Schenectady, NY |
Arrival: | Fort Edward, NY |
Fastest route: | 0h 46min |
Distance: | 66km |
Cheapest route: | $18 |
Transfers: | Between 0 and 1 |
Train companies: | Amtrak |
One Passenger / One Trip
10:28am
Schenectady, NY
Schenectady
12:23pm
Fort Edward, NY
Fort Edward-Glens Falls
1h 55min
+
$33
10:28am
Schenectady, NY
Schenectady
10:50am
Rensselaer, NY
Albany-Rensselaer
0h 22min
Amtrak
Ethan Allen Express
$13
0h 20min layover
11:10am
Rensselaer, NY
Albany-Rensselaer
12:23pm
Fort Edward, NY
Fort Edward-Glens Falls
1h 13min
Amtrak
Adirondack
$20
11:33am
Schenectady, NY
Schenectady
12:23pm
Fort Edward, NY
Fort Edward-Glens Falls
0h 50min
Amtrak
Adirondack
$18
5:28pm
Schenectady, NY
Schenectady
6:14pm
Fort Edward, NY
Fort Edward-Glens Falls
0h 46min
Amtrak
Ethan Allen Express
$18
The Schenectady - Fort Edward route has approximately 3 frequencies and its minimum duration is around 0h 46min. It is important you book your ticket in advance to avoid running out, since $18 tickets tend to run out quickly.
The distance between Schenectady and Fort Edward is around 66 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 0h 46min to cover 66 kilometers.
According to our data, the cheapest ticket costs $18 and leaves Schenectady. You will not have to do any transfers, the trip will go direct to Fort Edward-Glens Falls.
The last train leaves at 5:28pm from Schenectady and arrives at 6:14pm at Fort Edward-Glens Falls. It will take 0h 46min, its price is $18 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 0h 50min and the price is $18.