Departure: | Schenectady, NY |
Arrival: | Fort Edward, NY |
Fastest route: | 0h 46min |
Distance: | 66km |
Cheapest route: | $18 |
Transfers: | 0 |
Train companies: | Amtrak |
One Passenger / One Trip
11:33am
Schenectady, NY
Schenectady
12:23pm
Fort Edward, NY
Fort Edward-Glens Falls
0h 50min
Amtrak
Adirondack
$18
6:24pm
Schenectady, NY
Schenectady
7:10pm
Fort Edward, NY
Fort Edward-Glens Falls
0h 46min
Amtrak
Ethan Allen Express
$18
The Schenectady - Fort Edward route has approximately 2 frequencies and its minimum duration is around 0h 46min. It is important you book your ticket in advance to avoid running out, since $18 tickets tend to run out quickly.
The distance between Schenectady and Fort Edward is around 66 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 0h 46min to cover 66 kilometers.
According to our data, the cheapest ticket costs $18 and leaves Schenectady. You will not have to do any transfers, the trip will go direct to Fort Edward-Glens Falls.
The last train leaves at 6:24pm from Schenectady and arrives at 7:10pm at Fort Edward-Glens Falls. It will take 0h 46min, its price is $18 and the number of changes will be 0.
Yes, there are direct train routes, their duration is usually around 0h 50min and the price is $18.