Departure: | Waterbury, VT |
Arrival: | Cherry Hill, NJ |
Fastest route: | 11h 2min |
Distance: | 602km |
Cheapest route: | $99.25 |
Transfers: | 2 |
Train companies: | Amtrak |
One Passenger / One Trip
10:10am
Waterbury, VT
Waterbury-Stowe
9:12pm
Cherry Hill, NJ
Cherry Hill - NJ Transit Station
11h 2min
++
$99.25
10:10am
Waterbury, VT
Waterbury-Stowe
7:36pm
Trenton, NJ
Trenton
9h 26min
Amtrak
Vermonter
$72
0h 2min layover
7:38pm
Trenton, NJ
Trenton
8:07pm
Philadelphia, PA
Philadelphia - 30th Street Station
0h 29min
Amtrak
Vermonter
$23
0h 37min layover
8:44pm
Philadelphia, PA
Philadelphia - 30th Street Station
9:12pm
Cherry Hill, NJ
Cherry Hill - NJ Transit Station
0h 28min
Amtrak
NJ Transit Train
$4.25
The Waterbury - Cherry Hill route has approximately 1 frequencies and its minimum duration is around 11h 2min. It is important you book your ticket in advance to avoid running out, since $99.25 tickets tend to run out quickly.
The distance between Waterbury and Cherry Hill is around 602 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 11h 2min to cover 602 kilometers.
According to our data, the cheapest ticket costs $99.25 and leaves Waterbury-Stowe. If you decide to make this journey you will have to do 2 stops before reaching Cherry Hill - NJ Transit Station.
The last train leaves at 10:10am from Waterbury-Stowe and arrives at 9:12pm at Cherry Hill - NJ Transit Station. It will take 11h 2min, its price is $99.25 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 11h 2min