Departure: | Waterloo, IN |
Arrival: | Connellsville, PA |
Fastest route: | 8h 36min |
Distance: | 556km |
Cheapest route: | $67 |
Transfers: | Between 0 and 1 |
Train companies: | Amtrak |
One Passenger / One Trip
10:23pm
Waterloo, IN
Waterloo
6:59am
Connellsville, PA
Connellsville
8h 36min
Amtrak
Capitol Limited
$67
10:23pm
Waterloo, IN
Waterloo
6:59am
Connellsville, PA
Connellsville
8h 36min
+
$69
10:23pm
Waterloo, IN
Waterloo
1:45am
Cleveland, OH
Cleveland
3h 22min
Amtrak
Capitol Limited
$29
0h 9min layover
1:54am
Cleveland, OH
Cleveland
6:59am
Connellsville, PA
Connellsville
5h 5min
Amtrak
Capitol Limited
$40
The Waterloo - Connellsville route has approximately 2 frequencies and its minimum duration is around 8h 36min. It is important you book your ticket in advance to avoid running out, since $67 tickets tend to run out quickly.
The distance between Waterloo and Connellsville is around 556 kilometers and bus companies that can help you in your journey are: Amtrak.
The train journey may vary depending on the stops. The minimum duration is usually around 8h 36min to cover 556 kilometers.
According to our data, the cheapest ticket costs $67 and leaves Waterloo. You will not have to do any transfers, the trip will go direct to Connellsville.
The last train leaves at 10:23pm from Waterloo and arrives at 6:59am at Connellsville. It will take 8h 36min, its price is $69 and the number of changes will be 1.
Yes, there are direct train routes, their duration is usually around 8h 36min and the price is $67.