Departure: | Waterloo, IN |
Arrival: | Stanwood, WA |
Fastest route: | 28h 15min |
Distance: | 3460km |
Cheapest route: | $106 |
Transfers: | 2 |
Train companies: | Amtrak |
One Passenger / One Trip
4:05pm
Waterloo, IN
Waterloo
8:20pm
Stanwood, WA
Stanwood
28h 15min
++
$106
4:05pm
Waterloo, IN
Waterloo
7:51am
South Bend, IN
South Bend
15h 46min
Amtrak
Capitol Limited
$85
3h 39min layover
11:30am
South Bend, IN
South Bend
11:42am
Tukwila, WA
Tukwila
0h 12min
Amtrak
Amtrak Cascades
$7
6h 21min layover
6:03pm
Tukwila, WA
Tukwila
8:20pm
Stanwood, WA
Stanwood
2h 17min
Amtrak
Amtrak Cascades
$14
The Waterloo - Stanwood route has approximately 1 frequencies and its minimum duration is around 28h 15min. It is important you book your ticket in advance to avoid running out, since $106 tickets tend to run out quickly.
The distance between Waterloo and Stanwood is around 3460 kilometers and bus companies that can help you in your journey are: Amtrak.
Remember that the number of transfers to be made will be at least 2 so in some cases you should book the tickets separately.
The train journey may vary depending on the stops. The minimum duration is usually around 28h 15min to cover 3460 kilometers.
According to our data, the cheapest ticket costs $106 and leaves Waterloo. If you decide to make this journey you will have to do 2 stops before reaching Stanwood.
The last train leaves at 4:05pm from Waterloo and arrives at 8:20pm at Stanwood. It will take 28h 15min, its price is $106 and the number of changes will be 2.
We do not have direct routes in our database. The minimum number of transfers will be 2 transshipments and the total duration of the trip will be approximately 28h 15min